Physics

Bohr Model of Hydrogen

Physics·Revision Notes

Hydrogen Spectrum — Revision Notes

NEET UG
Version 1Updated 23 Mar 2026

⚡ 30-Second Revision

  • Energy Levels:En=13.6n2eVE_n = -\frac{13.6}{n^2}\,\text{eV} (for hydrogen)
  • Rydberg Formula:1λ=R(1nf21ni2)\frac{1}{\lambda} = R\left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right)
  • Rydberg Constant:R1.097×107 m1R \approx 1.097 \times 10^7 \text{ m}^{-1}
  • Lyman Series:nf=1n_f=1, ni=2,3,4,n_i=2,3,4,\dots, UV region
  • Balmer Series:nf=2n_f=2, ni=3,4,5,n_i=3,4,5,\dots, Visible & near-UV region
  • Paschen Series:nf=3n_f=3, ni=4,5,6,n_i=4,5,6,\dots, IR region
  • Brackett Series:nf=4n_f=4, ni=5,6,7,n_i=5,6,7,\dots, Far IR region
  • Pfund Series:nf=5n_f=5, ni=6,7,8,n_i=6,7,8,\dots, Far IR region
  • Series Limit:ni=n_i=\infty (shortest wavelength, highest energy)
  • First Line:ni=nf+1n_i=n_f+1 (longest wavelength, lowest energy within a series)

2-Minute Revision

The hydrogen spectrum is a set of discrete lines, not continuous, proving electron energy levels are quantized. Bohr's model explains this: electrons transition between fixed energy levels ($E_n = -13.

6/n^2\,\text{eV}),emittingorabsorbingphotons.TheRydbergformula,), emitting or absorbing photons. The Rydberg formula,\frac{1}{\lambda} = R\left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right),calculatesthewavelengthofthesephotons.Rememberthefivemainseries:Lyman(, calculates the wavelength of these photons. Remember the five main series: Lyman (n_f=1,UV),Balmer(, UV), Balmer (n_f=2,Visible/UV),Paschen(, Visible/UV), Paschen (n_f=3,IR),Brackett(, IR), Brackett (n_f=4,FarIR),andPfund(, Far IR), and Pfund (n_f=5$, Far IR).

The 'series limit' corresponds to ni=n_i=\infty, giving the shortest wavelength and highest energy for that series. The 'first line' corresponds to ni=nf+1n_i=n_f+1, giving the longest wavelength and lowest energy.

Higher energy transitions mean shorter wavelengths and higher frequencies. Be ready to apply these concepts to calculate wavelengths, energies, and identify spectral regions.

5-Minute Revision

The hydrogen spectrum is a critical topic, showcasing the quantum nature of atoms. It's characterized by discrete lines, explained by Bohr's model where electrons occupy quantized energy levels $E_n = -13.

6/n^2\,\text{eV}.Whenanelectrondropsfromahigherenergylevel(. When an electron drops from a higher energy level (n_i)toalowerone() to a lower one (n_f),itemitsaphoton.ThewavelengthofthisphotonisgivenbytheRydbergformula:), it emits a photon. The wavelength of this photon is given by the Rydberg formula:\frac{1}{\lambda} = R\left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right),where, whereRistheRydbergconstant(is the Rydberg constant (1.

097 \times 10^7 \text{ m}^{-1}).Remember). Remembern_i > n_f$ for emission.

Key Series to Master:

    1
  1. Lyman Series ($n_f=1$):Transitions from ni=2,3,4,n_i=2,3,4,\dots. All lines are in the Ultraviolet (UV) region.
  2. 2
  3. Balmer Series ($n_f=2$):Transitions from ni=3,4,5,n_i=3,4,5,\dots. Lines are in the Visible and near-UV region. This is the only series with visible lines (Hα,Hβ,Hγ,HδH_\alpha, H_\beta, H_\gamma, H_\delta).
  4. 3
  5. Paschen Series ($n_f=3$):Transitions from ni=4,5,6,n_i=4,5,6,\dots. All lines are in the Infrared (IR) region.
  6. 4
  7. Brackett Series ($n_f=4$):Transitions from ni=5,6,7,n_i=5,6,7,\dots. All lines are in the Far Infrared (IR) region.
  8. 5
  9. Pfund Series ($n_f=5$):Transitions from ni=6,7,8,n_i=6,7,8,\dots. All lines are in the Far Infrared (IR) region.

Important Concepts:

  • Series Limit:The shortest wavelength (highest energy) line in a series, occurring when ni=n_i = \infty. For example, for Lyman series limit, 1λ=R(11212)=R\frac{1}{\lambda} = R\left(\frac{1}{1^2} - \frac{1}{\infty^2}\right) = R.
  • First Line:The longest wavelength (lowest energy) line in a series, occurring when ni=nf+1n_i = n_f+1. For example, for Balmer's first line (HαH_\alpha), ni=3,nf=2n_i=3, n_f=2.
  • Excitation Energy:Energy needed to move an electron from a lower to a higher state, e.g., from n=1n=1 to n=2n=2 is E2E1=(3.4)(13.6)=10.2eVE_2 - E_1 = (-3.4) - (-13.6) = 10.2\,\text{eV}.
  • Ionization Energy:Energy needed to remove an electron completely from an atom (from nn to n=n=\infty). From ground state (n=1n=1), it's 13.6eV13.6\,\text{eV}. From an excited state nn, it's En=13.6/n2eV|E_n| = 13.6/n^2\,\text{eV}.

Example: Calculate the wavelength of the first line of the Paschen series. Here, nf=3n_f=3 and ni=4n_i=4. 1λ=R(132142)=R(19116)=R(169144)=7R144\frac{1}{\lambda} = R\left(\frac{1}{3^2} - \frac{1}{4^2}\right) = R\left(\frac{1}{9} - \frac{1}{16}\right) = R\left(\frac{16-9}{144}\right) = \frac{7R}{144}. λ=1447R=1447×1.097×1071.875×106m=1875nm\lambda = \frac{144}{7R} = \frac{144}{7 \times 1.097 \times 10^7} \approx 1.875 \times 10^{-6}\,\text{m} = 1875\,\text{nm} (IR region).

Prelims Revision Notes

The Hydrogen Spectrum is a crucial topic for NEET, primarily tested through the application of Bohr's model and the Rydberg formula. Key points for quick recall:

1. Bohr's Energy Levels:

* Energy of electron in nn-th orbit: En=13.6n2eVE_n = -\frac{13.6}{n^2}\,\text{eV}. * Ground state: n=1n=1, E1=13.6eVE_1 = -13.6\,\text{eV}. * First excited state: n=2n=2, E2=3.4eVE_2 = -3.4\,\text{eV}. * Second excited state: n=3n=3, E3=1.51eVE_3 = -1.51\,\text{eV}. * Energy levels get closer as nn increases.

2. Rydberg Formula for Wavelength:

* 1λ=R(1nf21ni2)\frac{1}{\lambda} = R\left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right), where ni>nfn_i > n_f for emission. * Rydberg constant R1.097×107 m1R \approx 1.097 \times 10^7 \text{ m}^{-1}. * For hydrogen-like ions (e.g., He+,Li2+He^+, Li^{2+}), use RZ2R Z^2 instead of RR.

3. Spectral Series (Memorize $n_f$ and EM Region):

* Lyman Series: nf=1n_f=1. Transitions from ni=2,3,4,n_i=2,3,4,\dots. Region: Ultraviolet (UV). * Balmer Series: nf=2n_f=2. Transitions from ni=3,4,5,n_i=3,4,5,\dots. Region: Visible (partially) and near-UV. * Paschen Series: nf=3n_f=3. Transitions from ni=4,5,6,n_i=4,5,6,\dots. Region: Infrared (IR). * Brackett Series: nf=4n_f=4. Transitions from ni=5,6,7,n_i=5,6,7,\dots. Region: Far Infrared (IR). * Pfund Series: nf=5n_f=5. Transitions from ni=6,7,8,n_i=6,7,8,\dots. Region: Far Infrared (IR).

4. Key Terms:

* First Line of a Series: Corresponds to the smallest energy transition within that series, i.e., ni=nf+1n_i = n_f+1. This gives the longest wavelength. * Series Limit: Corresponds to the largest energy transition within that series, i.

e., ni=n_i = \infty. This gives the shortest wavelength. * Ionization Energy: Energy to remove electron from nn to \infty. From ground state (n=1n=1), it's 13.6eV13.6\,\text{eV}. From state nn, it's $|E_n| = 13.

6/n^2\,\text{eV}.ExcitationEnergy:Energytomoveelectronfrom. * **Excitation Energy:** Energy to move electron fromn_ftoton_i..\Delta E = E_{n_i} - E_{n_f}$.

5. Energy-Wavelength-Frequency Relationship:

* E=hν=hc/λE = h\nu = hc/\lambda. Higher energy means higher frequency and shorter wavelength.

6. Common Traps:

* Confusing nin_i and nfn_f. * Mixing up series (e.g., calculating for Lyman when Balmer is asked). * Confusing 'first line' with 'series limit'. * Arithmetic errors, especially with squares and fractions.

Vyyuha Quick Recall

To remember the order of spectral series and their regions: Lazy Boys Play Baseball Professionally

  • Lyman (nf=1n_f=1) - Ultraviolet (UV)
  • Balmer (nf=2n_f=2) - Visible (and near UV)
  • Paschen (nf=3n_f=3) - Infrared (IR)
  • Brackett (nf=4n_f=4) - Infrared (IR)
  • Pfund (nf=5n_f=5) - Infrared (IR)

(For regions, think: UV, Visible, IR, IR, IR)

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