Physics

Bohr Model of Hydrogen

Physics·Explained

Energy Levels — Explained

NEET UG
Version 1Updated 23 Mar 2026

Detailed Explanation

The concept of energy levels is a cornerstone of atomic physics, particularly elucidated by Niels Bohr's model for the hydrogen atom. Before Bohr, classical physics struggled to explain the stability of atoms and the discrete nature of atomic spectra. Bohr's model, though superseded by more advanced quantum mechanics, provided a crucial stepping stone and remains highly relevant for understanding basic atomic structure and spectral phenomena, especially for hydrogen and hydrogen-like ions.

Conceptual Foundation: The Bohr Model's Postulates

Bohr's model is built upon three fundamental postulates:

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  1. Stationary Orbits:Electrons revolve around the nucleus in certain definite, non-radiating orbits, called stationary states or non-radiating orbits. In these orbits, the electron does not emit electromagnetic radiation, contrary to classical electromagnetism.
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  3. Quantization of Angular Momentum:The angular momentum of an electron in a stationary orbit is quantized. It can only take on discrete values that are integral multiples of h2π\frac{h}{2\pi}, where hh is Planck's constant. Mathematically, this is expressed as L=mvr=nh2πL = mvr = n\frac{h}{2\pi}, where mm is the electron's mass, vv is its speed, rr is the radius of the orbit, and nn is a positive integer (1, 2, 3, ...), known as the principal quantum number.
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  5. Energy Transitions:An electron can jump from one stationary orbit to another. When it jumps from a higher energy orbit (EiE_i) to a lower energy orbit (EfE_f), it emits a photon whose energy is exactly equal to the energy difference between the two orbits: hν=EiEfh\nu = E_i - E_f. Conversely, to jump from a lower to a higher energy orbit, the electron must absorb a photon of the same energy difference.

Key Principles and Derivations for Energy Levels

To derive the expression for the energy levels, we combine Bohr's postulates with classical mechanics and electrostatics.

Consider an electron of mass mm and charge e-e orbiting a nucleus of charge +Ze+Ze (where Z=1Z=1 for hydrogen) in a circular orbit of radius rr with speed vv.

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  1. Centripetal Force and Electrostatic Force:For a stable orbit, the electrostatic attractive force between the electron and the nucleus provides the necessary centripetal force.

Fcentripetal=FelectrostaticF_{\text{centripetal}} = F_{\text{electrostatic}}
mv2r=14πϵ0(Ze)(e)r2\frac{mv^2}{r} = \frac{1}{4\pi\epsilon_0} \frac{(Ze)(e)}{r^2}
mv2r=Ze24πϵ0r2(Equation 1)\frac{mv^2}{r} = \frac{Ze^2}{4\pi\epsilon_0 r^2} \quad \text{(Equation 1)}

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  1. Quantization of Angular Momentum (Bohr's Postulate):

mvr=nh2π(Equation 2)mvr = n\frac{h}{2\pi} \quad \text{(Equation 2)}
From Equation 2, we can express vv as v=nh2πmrv = \frac{nh}{2\pi mr}. Substitute this into Equation 1:
m(nh2πmr)21r=Ze24πϵ0r2m\left(\frac{nh}{2\pi mr}\right)^2 \frac{1}{r} = \frac{Ze^2}{4\pi\epsilon_0 r^2}
mn2h24π2m2r21r=Ze24πϵ0r2m\frac{n^2h^2}{4\pi^2 m^2 r^2} \frac{1}{r} = \frac{Ze^2}{4\pi\epsilon_0 r^2}
n2h24π2mr3=Ze24πϵ0r2\frac{n^2h^2}{4\pi^2 m r^3} = \frac{Ze^2}{4\pi\epsilon_0 r^2}
We can cancel r2r^2 from both sides and solve for rr (the radius of the nn-th orbit, rnr_n):
rn=n2h2ϵ0πmZe2(Equation 3 - Radius of n-th orbit)r_n = \frac{n^2h^2\epsilon_0}{\pi m Z e^2} \quad \text{(Equation 3 - Radius of n-th orbit)}
For hydrogen (Z=1Z=1) and n=1n=1, this gives the Bohr radius, $a_0 = \frac{h^2\epsilon_0}{\pi m e^2} \approx 0.

529 \times 10^{-10} \text{ m}.So,. So,r_n = n^2 a_0$.

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  1. Total Energy of the Electron:The total energy EE of the electron in an orbit is the sum of its kinetic energy (KE) and potential energy (PE).

KE=12mv2KE = \frac{1}{2}mv^2
PE=14πϵ0Ze2rPE = -\frac{1}{4\pi\epsilon_0} \frac{Ze^2}{r}
(The negative sign indicates an attractive force and that the electron is bound. Potential energy is zero when the electron is infinitely far from the nucleus).

From Equation 1, we have mv2=Ze24πϵ0rmv^2 = \frac{Ze^2}{4\pi\epsilon_0 r}. Substitute this into the KE expression:

KE=12(Ze24πϵ0r)=Ze28πϵ0rKE = \frac{1}{2} \left(\frac{Ze^2}{4\pi\epsilon_0 r}\right) = \frac{Ze^2}{8\pi\epsilon_0 r}
Now, sum KE and PE to get the total energy EnE_n for the nn-th orbit:
En=KE+PE=Ze28πϵ0rnZe24πϵ0rnE_n = KE + PE = \frac{Ze^2}{8\pi\epsilon_0 r_n} - \frac{Ze^2}{4\pi\epsilon_0 r_n}
En=Ze28πϵ0rn(Equation 4)E_n = -\frac{Ze^2}{8\pi\epsilon_0 r_n} \quad \text{(Equation 4)}
Notice that the total energy is negative and is half of the potential energy.

This is a characteristic of systems where the force is inversely proportional to the square of the distance (virial theorem).

Finally, substitute the expression for rnr_n from Equation 3 into Equation 4:

En=Ze28πϵ0(πmZe2n2h2ϵ0)E_n = -\frac{Ze^2}{8\pi\epsilon_0} \left(\frac{\pi m Z e^2}{n^2h^2\epsilon_0}\right)
En=mZ2e48ϵ02n2h2(Equation 5 - Energy of n-th level)E_n = -\frac{m Z^2 e^4}{8\epsilon_0^2 n^2 h^2} \quad \text{(Equation 5 - Energy of n-th level)}

For the hydrogen atom (Z=1Z=1), the energy levels are:

En=me48ϵ02h21n2E_n = -\frac{m e^4}{8\epsilon_0^2 h^2} \frac{1}{n^2}
The combination of constants me48ϵ02h2\frac{m e^4}{8\epsilon_0^2 h^2} is known as the Rydberg constant for energy, RHR_H. Its value is approximately 2.18×10182.18 \times 10^{-18} J or 13.613.6 eV. Thus, the energy levels for hydrogen are:
En=13.6n2 eVE_n = -\frac{13.6}{n^2} \text{ eV}

Significance of Negative Energy:

The negative sign for energy levels indicates that the electron is bound to the nucleus. Energy must be supplied to remove the electron from the atom. An electron with zero energy is considered free, i.e., it has just enough energy to escape the atom's influence (ionization). Positive energy would correspond to a free electron with kinetic energy, not bound to the nucleus.

Real-World Applications:

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  1. Hydrogen Spectrum:The most direct application is the explanation of the hydrogen line spectrum. When electrons transition between energy levels, they emit or absorb photons of specific energies, leading to distinct spectral lines (Lyman, Balmer, Paschen, Brackett, Pfund series). This was a major triumph of the Bohr model.
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  3. Lasers:The principle of discrete energy levels is fundamental to the operation of lasers. Atoms are excited to higher energy levels, and then stimulated emission occurs as electrons drop to lower levels, releasing coherent light.
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  5. Spectroscopy:The analysis of atomic and molecular spectra, based on energy level transitions, is a powerful tool in chemistry and physics for identifying substances and studying their properties.

Common Misconceptions:

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  1. Continuous Energy:A common mistake is to think that electrons can have any energy value. Bohr's model explicitly states that energy is quantized, meaning only specific, discrete energy levels are allowed.
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  3. Ground State Energy is Zero:The ground state (n=1n=1) has the lowest (most negative) energy, not zero. Zero energy corresponds to an ionized atom (electron completely removed).
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  5. Bohr Model is Universally Applicable:While revolutionary, the Bohr model is strictly applicable only to hydrogen and hydrogen-like ions (e.g., He+^+, Li2+^{2+}) because it does not account for electron-electron repulsion or more complex quantum mechanical effects like electron spin or orbital shapes.
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  7. Electrons 'Orbit' like Planets:While a useful analogy, electrons in reality do not follow well-defined classical orbits. Quantum mechanics describes them as probability distributions (orbitals).

NEET-Specific Angle:

For NEET, understanding the formula En=13.6Z2n2 eVE_n = -\frac{13.6 Z^2}{n^2} \text{ eV} is crucial. You should be able to:

  • Calculate the energy of an electron in a specific orbit for hydrogen or hydrogen-like ions.
  • Calculate the energy difference between two levels, which corresponds to the energy of an emitted or absorbed photon (hν=hcλ=EiEfh\nu = \frac{hc}{\lambda} = E_i - E_f).
  • Relate energy transitions to the different spectral series (Lyman, Balmer, Paschen, etc.) and their corresponding regions of the electromagnetic spectrum.
  • Determine ionization energy (energy required to remove an electron from the ground state to n=n=\infty).
  • Understand the relationship between energy levels and the principal quantum number nn: as nn increases, energy levels become less negative and closer together. The spacing between adjacent levels decreases rapidly with increasing nn.
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