Chemistry·MCQ Practice

Thermodynamic Principles of Metallurgy — MCQ Practice

NEET UG
Version 1Updated 22 Mar 2026

Interactive MCQ Practice

Test your knowledge. Click “Solve” to reveal options, select your answer, then check the result. 6 questions available.

Q1medium

Which of the following statements regarding the Ellingham diagram for metal oxides is INCORRECT?

Q2medium

At what approximate temperature does carbon become a more effective reducing agent than carbon monoxide for iron oxides, according to a typical Ellingham diagram?

Q3easy

Which of the following metals cannot be extracted by reduction with carbon at high temperatures, based on thermodynamic principles?

Q4easy

For the reaction 2M(s)+O2(g)2MO(s)2M(s) + O_2(g) \rightarrow 2MO(s), what would be the expected sign of ΔS\Delta S and the slope of its Ellingham diagram line?

Q5medium

Consider the following reactions:\nI. 2C(s)+O2(g)2CO(g)2C(s) + O_2(g) \rightarrow 2CO(g)\nII. 2CO(g)+O2(g)2CO2(g)2CO(g) + O_2(g) \rightarrow 2CO_2(g)\nIII. 2Mg(s)+O2(g)2MgO(s)2Mg(s) + O_2(g) \rightarrow 2MgO(s)\nWhich of these reactions would show a decreasing ΔG\Delta G^\circ with increasing temperature on an Ellingham diagram?

Q6hard

Given the following standard Gibbs free energy changes for oxide formation at a certain high temperature T:\nΔG(ZnO)=350 kJ/mol\Delta G^\circ (ZnO) = -350 \text{ kJ/mol} (for Zn+12O2ZnOZn + \frac{1}{2}O_2 \rightarrow ZnO)\nΔG(CO)=400 kJ/mol\Delta G^\circ (CO) = -400 \text{ kJ/mol} (for C+12O2COC + \frac{1}{2}O_2 \rightarrow CO)\nWhich of the following statements is correct regarding the reduction of ZnOZnO by carbon at temperature T?

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