Chemistry·Revision Notes

Bond Enthalpy and Bond Order — Revision Notes

NEET UG
Version 1Updated 22 Mar 2026

⚡ 30-Second Revision

  • Bond Enthalpy ($E_b$):Energy to break 1 mole of bonds (gaseous state). Always positive (endothermic). Unit: kJ/mol.
  • Bond Order (BO):Number of bonds between atoms.

- Lewis: 1 (single), 2 (double), 3 (triple). - MO Theory: BO=12(NbNa)\text{BO} = \frac{1}{2}(N_b - N_a).

  • Relationships:Higher BO     \implies Shorter Bond Length     \implies Higher EbE_b.
  • $\Delta H_{rxn}$ from $E_b$:ΔHrxn=Eb(bonds broken)Eb(bonds formed)\Delta H_{rxn} = \sum E_{b}(\text{bonds broken}) - \sum E_{b}(\text{bonds formed}).
  • MO Energy Order:

- 14\le 14 e: σ1s<σ1s<σ2s<σ2s<(π2p=π2p)<σ2p<(π2p=π2p)<σ2p\sigma_{1s} < \sigma_{1s}^* < \sigma_{2s} < \sigma_{2s}^* < (\pi_{2p} = \pi_{2p}) < \sigma_{2p} < (\pi_{2p}^* = \pi_{2p}^*) < \sigma_{2p}^*. - >14> 14 e: σ1s<σ1s<σ2s<σ2s<σ2p<(π2p=π2p)<(π2p=π2p)<σ2p\sigma_{1s} < \sigma_{1s}^* < \sigma_{2s} < \sigma_{2s}^* < \sigma_{2p} < (\pi_{2p} = \pi_{2p}) < (\pi_{2p}^* = \pi_{2p}^*) < \sigma_{2p}^*.

  • Magnetic Properties:Paramagnetic (unpaired e-), Diamagnetic (all paired e-).

2-Minute Revision

Bond enthalpy is the energy absorbed to break a chemical bond, signifying its strength. It's an average value for polyatomic molecules. Factors like bond order, bond length, atomic size, and electronegativity difference dictate its magnitude; stronger bonds have higher enthalpy.

Bond order quantifies the number of bonds between atoms, directly influencing bond strength and inversely influencing bond length. For simple molecules, it's an integer (1, 2, 3). For resonance structures or using Molecular Orbital (MO) theory, it can be fractional.

MO theory calculates bond order as half the difference between bonding and antibonding electrons (NbNaN_b - N_a). This theory is crucial for predicting magnetic properties (paramagnetic if unpaired electrons, diamagnetic if all paired) and for comparing the stability and bond lengths of diatomic ions.

Remember the specific MO energy level order for molecules with 14\le 14 electrons versus >14> 14 electrons. Enthalpy changes of reactions can be estimated by summing the energy of bonds broken in reactants and subtracting the energy of bonds formed in products.

5-Minute Revision

To master bond enthalpy and bond order, begin by solidifying definitions. Bond enthalpy is the energy required to break a bond (endothermic, positive value), while bond order is the number of bonds between atoms. These are inversely related to bond length: higher bond order means shorter bond length and stronger bond, hence higher bond enthalpy. For example, a C≡C bond (BO=3) is shorter and stronger than a C=C bond (BO=2), which is shorter and stronger than a C-C bond (BO=1).

For calculating reaction enthalpy (ΔHrxn\Delta H_{rxn}), use the formula: ΔHrxn=Eb(bonds broken)Eb(bonds formed)\Delta H_{rxn} = \sum E_{b}(\text{bonds broken}) - \sum E_{b}(\text{bonds formed}). Always draw out the structures to correctly count each type of bond.

For instance, in H2(g)+Cl2(g)2HCl(g)\text{H}_2(g) + \text{Cl}_2(g) \to 2\text{HCl}(g), you break one H-H and one Cl-Cl bond, and form two H-Cl bonds. If Eb(HH)=436E_{b}(\text{H}-\text{H}) = 436, Eb(ClCl)=242E_{b}(\text{Cl}-\text{Cl}) = 242, Eb(HCl)=431E_{b}(\text{H}-\text{Cl}) = 431, then ΔHrxn=(436+242)(2×431)=184 kJ/mol\Delta H_{rxn} = (436+242) - (2 \times 431) = -184 \text{ kJ/mol}.

Molecular Orbital (MO) theory is vital for diatomic species. First, count total electrons. Then, fill them into MOs following the correct energy order: for 14\le 14 electrons, π2p\pi_{2p} are lower than σ2p\sigma_{2p}; for >14> 14 electrons, σ2p\sigma_{2p} is lower than π2p\pi_{2p}.

Calculate bond order as 12(NbNa)\frac{1}{2}(N_b - N_a). For example, O2\text{O}_2 (16 electrons) has MO config (σ1s)2(σ1s)2(σ2s)2(σ2s)2(σ2p)2(π2p)4(π2p)2(\sigma_{1s})^2 (\sigma_{1s}^*)^2 (\sigma_{2s})^2 (\sigma_{2s}^*)^2 (\sigma_{2p})^2 (\pi_{2p})^4 (\pi_{2p}^*)^2.

Here, Nb=10,Na=6N_b=10, N_a=6, so BO=2. The two unpaired electrons in π2p\pi_{2p}^* make O2\text{O}_2 paramagnetic. Compare O2+\text{O}_2^+ (15e, BO=2.5) and O2\text{O}_2^- (17e, BO=1.5) to understand how adding/removing electrons affects bond order, length, and enthalpy.

Remember, higher bond order means shorter bond length and higher bond enthalpy. Practice these calculations and comparisons rigorously.

Prelims Revision Notes

Bond Enthalpy and Bond Order: NEET Quick Revision

1. Bond Enthalpy ($E_b$ or $\Delta H_{bond}$):

  • Definition:Average energy required to break one mole of a specific type of bond in the gaseous state.
  • Nature:Always positive (endothermic process). Energy is absorbed to break bonds.
  • Units:Kilojoules per mole (kJ/mol).
  • Bond Dissociation Enthalpy (BDE):Energy to break a *specific* bond in a *specific* molecule. Differs from average bond enthalpy for polyatomic molecules.
  • **Factors Affecting EbE_b:**

* Bond Order: Higher BO     \implies Higher EbE_b. * Bond Length: Shorter bond length     \implies Higher EbE_b. * Atomic Size: Smaller atoms     \implies Shorter bonds     \implies Higher EbE_b. * Electronegativity Difference: Greater difference     \implies More polar bond     \implies Stronger bond     \implies Higher EbE_b.

  • **Calculation of ΔHrxn\Delta H_{rxn}:**

* ΔHrxn=Eb(bonds broken in reactants)Eb(bonds formed in products)\Delta H_{rxn} = \sum E_{b}(\text{bonds broken in reactants}) - \sum E_{b}(\text{bonds formed in products}) * Remember to multiply bond enthalpies by stoichiometric coefficients and the number of identical bonds within a molecule.

2. Bond Order (BO):

  • Definition:Number of chemical bonds between a pair of atoms.
  • From Lewis Structures:

* Single bond: BO = 1 * Double bond: BO = 2 * Triple bond: BO = 3 * Resonance structures: Fractional BO (e.g., benzene C-C bond order = 1.5).

  • From Molecular Orbital (MO) Theory (for diatomic species):

* Formula: Bond Order=12(NbNa)\text{Bond Order} = \frac{1}{2} (N_b - N_a) * NbN_b: Number of electrons in bonding molecular orbitals. * NaN_a: Number of electrons in antibonding molecular orbitals. * MO Energy Level Order: * **For 14\le 14 electrons (e.

g., H2,N2,C2,B2\text{H}_2, \text{N}_2, \text{C}_2, \text{B}_2):** σ1s<σ1s<σ2s<σ2s<(π2p=π2p)<σ2p<(π2p=π2p)<σ2p\sigma_{1s} < \sigma_{1s}^* < \sigma_{2s} < \sigma_{2s}^* < (\pi_{2p} = \pi_{2p}) < \sigma_{2p} < (\pi_{2p}^* = \pi_{2p}^*) < \sigma_{2p}^* * **For >14> 14 electrons (e.

g., O2,F2,Ne2\text{O}_2, \text{F}_2, \text{Ne}_2):** σ1s<σ1s<σ2s<σ2s<σ2p<(π2p=π2p)<(π2p=π2p)<σ2p\sigma_{1s} < \sigma_{1s}^* < \sigma_{2s} < \sigma_{2s}^* < \sigma_{2p} < (\pi_{2p} = \pi_{2p}) < (\pi_{2p}^* = \pi_{2p}^*) < \sigma_{2p}^* * Magnetic Properties: * Paramagnetic: Contains one or more unpaired electrons (e.

g., O2,NO\text{O}_2, \text{NO}). Attracted to a magnetic field. * Diamagnetic: All electrons are paired (e.g., N2,F2\text{N}_2, \text{F}_2). Repelled by a magnetic field.

3. Interrelationship of Bond Parameters:

  • **Higher Bond Order     \implies Shorter Bond Length     \implies Higher Bond Enthalpy     \implies Greater Stability.**
  • A bond order of zero implies no stable molecule (e.g., He2\text{He}_2).

Key Strategy: Practice MO configurations and bond order calculations for various diatomic species and their ions. Be meticulous in counting bonds for enthalpy calculations.

Vyyuha Quick Recall

Bond Order Length Enthalpy: Bigger Order, Less Length, More Enthalpy. (Think BOLLE - 'Bigger Order, Less Length, More Enthalpy')

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